Question

\(\sqrt{x^2-6x+25}\) = 4

Answer 1

\(\left(\sqrt{x^2-6x+25}\right)^2=16\\ x^2-6x+25-16=0\\ x^2-6x+9=0\\ \left(x-3\right)^2=0\\ x=3\)

Answer 2

=>x^2-6x+25=16

=>x^2-6x+9=0

=>x=3