Lời giải:
Xét hiệu:
\(\sqrt{33}-\sqrt{17}-(6-\sqrt{15})=(\sqrt{33}-6)+(\sqrt{15}-\sqrt{17})\)
\(< (\sqrt{36}-6)+(\sqrt{17}-\sqrt{17})=0+0=0\)
\(\Rightarrow \sqrt{33}-\sqrt{17}< 6-\sqrt{15}\)
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\(\sqrt{3\sqrt{2}}=\sqrt{\sqrt{3^2.2}}=\sqrt[4]{18}\)
\(\sqrt{2\sqrt{3}}=\sqrt{\sqrt{2^2.3}}=\sqrt[4]{12}\)
Mà \(18>12\Rightarrow \sqrt[4]{18}>\sqrt[4]{12}\Rightarrow \sqrt{3\sqrt{2}}>\sqrt{2\sqrt{3}}\)