Question

Q\(=\left(\dfrac{1}{x-\sqrt{x}}+\dfrac{1}{\sqrt{x}-1}\right)\div\dfrac{\sqrt{x}+1}{x-2\sqrt{x}+1}\)

a) tìm x để biểu thứcQ có nghĩa

Answer 1

\(a,ĐK:x\ge0;x\ne1\\ Q=\dfrac{1+\sqrt{x}}{\sqrt{x}\left(\sqrt{x}-1\right)}\cdot\dfrac{\left(\sqrt{x}-1\right)^2}{\sqrt{x}+1}\\ Q=\dfrac{\sqrt{x}-1}{\sqrt{x}}\)