Question

Phân tích đa thức thành nhân tử 
y^2-(x^2-2x+1)

Answer 1

\(y^2-\left(x^2-2x+1\right)=y^2-\left(x-1\right)^2=\left(y-x+1\right)\left(y+x-1\right)\)

Answer 2

\(y^2-\left(x^2-2x+1\right)=y^2-\left(x-1\right)^2=\left(y-x+1\right).\left(y+x-1\right)\)

Answer 3

     y\(^2\) - ( x\(^2\) - 2x + 1 )

⇔ y\(^2\) - ( x - 1 )\(^2\)

⇔ ( y - x - 1 ) ( y + x - 1 )

Answer 4

\(y^2-\left(x^2-2x+1\right)\)

\(=y^2-\left(x-1\right)^2\)

\(=\left(y-x+1\right)\left(y+x-1\right)\)