Question

phân tích đa thức thành nhân tử: 9a²b+6ab²+b³-6ab-2b²

Answer 1

\(=b\left(9a^2+6ab+b^2\right)-2b\left(3a+b\right)\)

\(=b\left(3a+b\right)^2-2b\left(3a+b\right)\)

\(=b\left(3a+b\right)\left(3a+b-2\right)\)

 

Answer 2

\(9a^2b+6ab^2+b^3-6ab-2b^2\)

\(=b\left(9a^2+6ab+b^2-6a-2b\right)\)

\(=b\left[\left(3a+b\right)^2-2\left(3a+b\right)\right]\)

\(=b\left(3a+b\right)\left(3a+b-2\right)\)