a) Ta có: \(\dfrac{x}{27}=\dfrac{-2}{3.6}\)
nên \(x=\dfrac{-2\cdot27}{3.6}=\dfrac{-54}{3.6}=-15\)
b) Ta có: \(-0.52:x=-9.36:16.38\)
\(\Leftrightarrow x=\dfrac{-0.52}{-9.36:16.38}\)
\(\Leftrightarrow x=\dfrac{0.52}{9.36:16.38}\)
\(\Leftrightarrow x=\dfrac{91}{100}\)
c) Ta có: \(\dfrac{x}{-15}=\dfrac{-60}{x}\)
\(\Leftrightarrow x^2=900\)
hay \(x\in\left\{30;-30\right\}\)
d) Ta có: \(0,25\cdot x:3=0,125\)
\(\Leftrightarrow0,25\cdot x=0,375\)
hay x=1,5