12=3.2*2(* là mũ ạ)
15=3.5
=>3.2*2.5=60
=> mc là 60 ạ
12=3.2*2(* là mũ ạ)
15=3.5
=>3.2*2.5=60
=> mc là 60 ạ
tìm 2 số a, b biết (a+b)=7 ; (a.b)=-8
lười làm quá !a làm dùm đi
Tìm x ϵ Z, biết:
\(\dfrac{5}{17}\)+\(\dfrac{-4}{9}\)+-\(\dfrac{20}{31}\)+\(\dfrac{12}{17}\)+\(\dfrac{-11}{-31}\)< \(\dfrac{x}{9}\) ≤ \(\dfrac{-3}{7}\)+\(\dfrac{7}{15}\)+\(\dfrac{4}{-7}\)+\(\dfrac{8}{15}\)+\(\dfrac{2}{3}\)
\(\dfrac{12}{-17}-\dfrac{8}{16}\) Lười lm qá...=((
\(\dfrac{-5}{12}\).\(\dfrac{7}{15}\)\(+\)\(\dfrac{-5}{12}\)\(+\)\(\dfrac{8}{15}\)\(+\)\(\dfrac{5}{12}\)
Tính:
a) \(\dfrac{-5}{9}\)\(+\dfrac{8}{15}+\dfrac{-2}{11}+\dfrac{4}{-9}+\dfrac{7}{15}\)
b)\(\left(\dfrac{-5}{12}+\dfrac{6}{11}\right)+\left(\dfrac{7}{17}+\dfrac{5}{11}+\dfrac{5}{12}\right)\)
c) A= \(49\dfrac{8}{23}-\left(5\dfrac{7}{32}+14\dfrac{8}{23}\right)\)
d) C= \(\dfrac{-3}{7}.\dfrac{5}{9}+\dfrac{4}{9}.\dfrac{-3}{7}+2\dfrac{3}{7}\)
\(\dfrac{-1}{3}.\dfrac{2}{5}\)
\(\dfrac{-3}{7}.\dfrac{4}{15}\)
\(\dfrac{-9}{3}.\dfrac{15}{27}\)
\(\dfrac{-5}{6}.\)( -12 )
\(\dfrac{-12}{4}.\dfrac{8}{9}\)
\(-3.\dfrac{7}{6}\)
\(\dfrac{-15}{9}.\dfrac{27}{5}\)
\(-9.\dfrac{4}{27}\)
bài 1:tính
a)\(\left(\dfrac{-7}{15}-\dfrac{27}{70}\right)-\left(\dfrac{8}{15}+\dfrac{43}{70}\right)\)
b)\(\dfrac{3}{7}+\left(\dfrac{-1}{5}+\dfrac{-3}{7}\right)\)
c)\(\left(4-\dfrac{12}{5}\right).\dfrac{25}{8}-\dfrac{2}{5}:\dfrac{-4}{25}\)
d)\(\left(\dfrac{-5}{24}+\dfrac{3}{4}-\dfrac{7}{12}\right):\left(-\dfrac{5}{16}\right)\)
e)\(\dfrac{-5}{7}.\dfrac{2}{11}+\dfrac{-5}{7}.\dfrac{9}{11}\)
g)\(\dfrac{6}{7}+\dfrac{5}{4}:\left(-5\right)-\dfrac{-1}{28}.\left(-2\right)^2\)
Quy đồng mẫu các phân số
b) \(\dfrac{17}{12}\) ; \(\dfrac{31}{18}\) ; \(\dfrac{8}{15}\)
c) \(\dfrac{7}{15}\) ; \(\dfrac{8}{25}\) ; \(\dfrac{11}{75}\)
d) \(\dfrac{8}{45}\) ; \(\dfrac{13}{180}\) ; \(\dfrac{4}{30}\)
e) \(\dfrac{51}{136}\) ; \(\dfrac{60}{108}\) ; \(\dfrac{26}{156}\)
giải nhanh giúp t vs ccau ơi, nhanh + chi tiết = tick
\(\dfrac{-1}{7}-\dfrac{1}{8}\)
\(\dfrac{-15}{48}-\dfrac{1}{12}\)
\(\dfrac{-3}{4}-\dfrac{4}{5}\)
\(\dfrac{3}{4}+\dfrac{-5}{6}-\dfrac{11}{12}\)