`12/[-17]-8/16=[-192]/272-136/272=-328/272=-41/34`
`12/(-17)-8/16`
`=-12/17-1/2`
`=-24/34 -17/34`
`=-41/34`
`12/[-17]-8/16=[-192]/272-136/272=-328/272=-41/34`
`12/(-17)-8/16`
`=-12/17-1/2`
`=-24/34 -17/34`
`=-41/34`
bài 1 tính :
\(\dfrac{-8}{9}\) . \(\dfrac{12}{19}\) . \(\dfrac{9}{-4}\) . \(\dfrac{19}{24}\) \(\dfrac{-5}{16}\) . \(\dfrac{17}{15}\) : \(\dfrac{-17}{8}\)
\(\dfrac{4}{13}\) . \(\dfrac{2}{7}\) + \(\dfrac{-3}{26}\) + \(\dfrac{4}{13}\) . \(\dfrac{5}{7}\) \(\dfrac{6}{11}\) . \(\dfrac{3}{4}\) + \(\dfrac{-12}{60}\) +\(\dfrac{-3}{4}\) .\(\dfrac{-5}{11}\)
bài 1 quy đồng mẫu các phân số
a,\(\dfrac{3}{8}và\dfrac{5}{12}\)
b,\(\dfrac{-2}{9}và\dfrac{5}{-12}\)
c,\(\dfrac{-3}{16};\dfrac{5}{-24};\dfrac{-21}{56}\)
d,\(\dfrac{17}{60};\dfrac{5}{18};\dfrac{64}{90}\)
lười quá nhờ tìm dùm MC nhá MC hoi ko cần nhìu
\(\dfrac{-7}{12};\dfrac{-8}{15}\)
bài 3 thực hiện phép tính
a\(\dfrac{5}{8}+\dfrac{3}{17}+\dfrac{4}{18}+\dfrac{20}{-17}+\dfrac{-2}{9}+\dfrac{21}{56}\)
b\(\left(\dfrac{9}{16}+\dfrac{8}{-27}\right)+\left(1+\dfrac{7}{16}+\dfrac{-19}{27}\right)\)
c\(\left(\dfrac{13}{5}+\dfrac{7}{16}\right)+\left(\dfrac{-15}{16}+\dfrac{6}{15}\right)\) d \(\left(6-2\dfrac{4}{5}\right).3\dfrac{1}{8}-1\dfrac{3}{5}:\dfrac{1}{4}\)
Tính hợp lý:
\(a.\dfrac{3}{17}+\dfrac{-5}{13}+\dfrac{-18}{35}+\dfrac{14}{17}+\dfrac{17}{-35}+\dfrac{-8}{13}\)
\(b.\dfrac{-3}{8}\cdot\dfrac{1}{6}+\dfrac{3}{-8}\cdot\dfrac{5}{6}+\dfrac{-10}{16}\)
\(c.\dfrac{-4}{11}\cdot\dfrac{5}{15}\cdot\dfrac{11}{-4}\)
Bài 1.Tính
a)\(\dfrac{4}{28}\)+\(\dfrac{12}{36}\) b)\(\dfrac{-12}{18}\)+\(\dfrac{15}{-21}\) c)\(\dfrac{14}{28}\)-\(\dfrac{-16}{32}\)-\(\dfrac{17}{51}\)
Tính một cách hợp lý : \(\dfrac{5}{17}.\dfrac{7}{11}+\dfrac{5}{17}.\dfrac{4}{11}+\dfrac{-12}{17}\) là
A. \(\dfrac{17}{-17}\) B. \(\dfrac{8}{17}\)
C. \(\dfrac{-7}{17}\) D. \(-\dfrac{-7}{17}\)
Tính
\(\dfrac{-3}{8}.\dfrac{17}{31}.\dfrac{-16}{9}.\dfrac{-93}{34}\)
C = \(\dfrac{4}{9}\)\(\times\)\(\dfrac{13}{17}\)+\(\dfrac{4}{17}\)\(\times\)\(\dfrac{4}{9}\)+\(\dfrac{2}{9}\)
D = \(\dfrac{8}{19}\)\(\times\)\(\dfrac{5}{11}\)+\(\dfrac{7}{11}\)\(\times\dfrac{8}{19}+\dfrac{12}{11}\times\dfrac{11}{19}\)