\(\left(2x-1\right)^3=27\)
\(\Rightarrow\left(2x-1\right)^3=3^3\)
\(\Rightarrow2x-1=3\)
\(\Rightarrow2x=3+1\)
\(\Rightarrow2x=4\)
\(\Rightarrow x=\dfrac{4}{2}\)
\(\Rightarrow x=2\)
\(\frac{17}{2}-\left|2x-\frac{3}{4}\right|=-\frac{7}{4}\)
\(\left(x+\frac{1}{5}\right)^2+\frac{17}{25}=\frac{26}{25}\)
\(-1\frac{5}{27}-\left(3x-\frac{7}{9}\right)^3=-\frac{24}{27}\)
Tìm x biết
25÷x=x. 3358÷23=2x-6
\(\left(2X+1\right)^3=27\)
\((X-2)^3=\left(X-2\right)^2\)
\(8^{2x+1}=2^{27}:4^6\)
\(x^{10}=x\)
\(\left(3x-1\right)^3=25\left(3x-1\right)\)
Tìm x
a)\(\left(3x-1\right)^3=25.\left(3x-1\right)\)
b)\(3^{2x+2}=9^{x+3}\)
c)\(8^{2x+1}=2^{27}:4^6\)
d)\(2.3^x=10.3^{12}+8.27^4\)
e)\(\left(3x-14\right)^3=2^5+5^2+200\)
\(\left(2x-1\right)^3=27\) tìm x thuộcN
Tìm \(\dfrac{\left(\left(4\right)^{-2}:\left(\dfrac{1}{3}\right)^2\right)\dfrac{^1}{2}}{\left(-\dfrac{1}{6}\right)^2}\)
A. 36 B.27 C. 48 D.- 36 E.-27
bài 1: tìm số nguyên x, biết
a) \(\left(25-2x\right)^3\): 5 - \(3^2\)= \(4^2\) b) 2 x \(3^x\)= \(10\) x \(3^{12}\) + 8 x \(27^4\)
\(3^X×3^2=729\:\:\:\:\:\:\\ 5^X×625=3125\\ \left(2X+1\right)^3=27\\ ^{ }\)
Tìm x
tìm x
a, \(\left(2x-\frac{1}{2}\right)^3=27\)
b, \(\left(3x+\frac{1}{2}\right)^{x-1}=1\)
c, \(\left(3x-5\right)^2=81\)
d, \(\left(\frac{3}{2}-x\right).\left(4x+8\right)=0\)
