Question

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Answer 1

#\(N\)

`d, -7/9 . 3/11 + 7/-9 . 8/11 - -16/9`

`= -7/9 . (3/11 + 8/11) + 16/9`

`= -7/9 . 1 + 16/9`

`=-7/9 + 16/9`

`=9/9=1`

`e, 2/7 . -5/6 + 2/-7 . 1/6 +5/7 -7`

`= -2/7 . (5/6 + 1/6) + 5/7 -7`

`= -2/7 . 1 + 5/7 -7`

`= -2/7 + 5/7 -7`

`= 3/7 - 7 =-46/7`

`g, 34/45 . 18/17 + 34/45 . 9/-17 - -34/45 . 10/17`

`= 34/45 . 18/17 + 34/45 . 9/-17 + 34/45 . 10/17`

`= 34/45 . (18/17 + -9/17 + 10/17)`

`= 34/45 . 19/17`

`=38/45`

Answer 2

d: \(=\dfrac{-7}{9}\left(\dfrac{3}{11}+\dfrac{8}{11}\right)+\dfrac{16}{9}=\dfrac{-7}{9}+\dfrac{16}{9}=1\)

e: \(=\dfrac{2}{7}\left(-\dfrac{5}{6}-\dfrac{1}{6}\right)+\dfrac{5}{7}-7=-\dfrac{2}{7}+\dfrac{5}{7}-7=-7+\dfrac{3}{7}=\dfrac{-46}{7}\)

g: \(=\dfrac{34}{45}\left(\dfrac{18}{17}-\dfrac{9}{17}+\dfrac{10}{17}\right)=\dfrac{34}{45}\)

Answer 3

cứu

Answer 4

\(d,\dfrac{-7}{9}.\dfrac{3}{11}+\dfrac{-7}{9}.\dfrac{8}{11}-\dfrac{-16}{9}=\dfrac{-7}{9}.\dfrac{3}{11}+\dfrac{-7}{9}.\dfrac{8}{11}+\dfrac{16}{9}=\dfrac{-7}{9}.\left(\dfrac{3}{11}+\dfrac{8}{11}\right)+\dfrac{16}{9}=\dfrac{-7}{9}.1+\dfrac{16}{9}=\dfrac{-7}{9}+\dfrac{16}{9}=\dfrac{9}{9}=1\)

\(e,\dfrac{2}{7}.\dfrac{-5}{6}+\dfrac{-2}{7}.\dfrac{1}{6}+\dfrac{5}{7}-7=\dfrac{-2}{7}.\left(\dfrac{5}{6}+\dfrac{1}{6}\right)+\dfrac{5}{7}-7=\dfrac{-2}{7}.1+\dfrac{5}{7}-7=\dfrac{-2}{7}+\dfrac{5}{7}-7=\dfrac{3}{7}-7=\dfrac{3}{7}-\dfrac{49}{7}=\dfrac{-46}{7}\)\(f,\dfrac{34}{45}.\dfrac{18}{17}+\dfrac{34}{45}.\dfrac{-9}{17}-\dfrac{-34}{45}.\dfrac{10}{17}=\dfrac{34}{45}.\dfrac{18}{17}+\dfrac{34}{45}.\dfrac{-9}{17}+\dfrac{34}{45}.\dfrac{10}{17}=\dfrac{34}{45}.\left(\dfrac{18}{17}+\dfrac{-9}{17}+\dfrac{10}{17}\right)=\dfrac{34}{45}.\dfrac{19}{17}=\dfrac{646}{765}=\dfrac{38}{45}\)