Question

giúp mìn với

 

Answer 1

Câu 1:

1) ĐKXĐ: \(-2x+5\ge0\Leftrightarrow x\le\dfrac{5}{2}\)

2) ĐKXĐ: \(-x+1>0\Leftrightarrow x< 1\)

Câu 2:

1) \(=6\sqrt{2}+3\sqrt{2}-10\sqrt{2}+3\sqrt{3}=3\sqrt{3}-\sqrt{2}\)

2) \(=5-3+\sqrt{2}-1=1+\sqrt{2}\)

3) \(=15-3+5\sqrt{15}=12+5\sqrt{15}\)

4) \(=\dfrac{\sqrt{3}}{2}+\dfrac{\sqrt[]{3}}{3}+\dfrac{\sqrt{3}}{6}=\dfrac{3\sqrt{3}+2\sqrt{3}+\sqrt{3}}{6}=\dfrac{6\sqrt{3}}{6}=\sqrt{3}\)

Answer 2

Câu 1: 

1: ĐKXĐ: \(x\le\dfrac{5}{2}\)

2: ĐKXĐ: x<1