Bài 1:a: \(\Leftrightarrow\left(3x+2\right)^2-6\left(3x-2\right)=9x^2\)\(\Leftrightarrow9x^2+12x+4-18x+12=9x^2\)=>-6x+16=0=>-6x=-16=>x=8/3b: \(\Leftrightarrow3\left(3-x\right)+2\left(5x-1\right)=4\)=>9-3x+10x-2=4=>7x+7=4=>7x=-3=>x=-3/7c: \(\Leftrightarrow-3\left(4x+1\right)=2\left(4x-1\right)-6x-8\)=>\(-12x-3=8x-2-6x-8=2x-10\)=>-14x=-7=>x=1/2d: \(\Leftrightarrow\dfrac{5-x}{4x\left(x-2\right)}+\dfrac{7}{8x}=\dfrac{x-1}{2x\left(x-2\right)}+\dfrac{1}{8\left(x-2\right)}\)\(\Leftrightarrow2\left(5-x\right)+7\left(x-2\right)=4\left(x-1\right)+x\)=>\(10-2x+7x-14=4x-4+x=5x-4\)=>5x-4=5x-4(luôn đúng)=>S=R\{0;2}e: \(\Leftrightarrow x^3+1-x^3+1=\dfrac{3}{x}\)=>\(2x=3\)=>x=3/2Câu trả lời: Bài 1:a: \(\Leftrightarrow\left(3x+2\right)^2-6\left(3x-2\right)=9x^2\)\(\Leftrightarrow9x^2+12x+4-18x+12=9x^2\)=>-6x+16=0=>-6x=-16=>x=8/3b: \(\Leftrightarrow3\left(3-x\right)+2\left(5x-1\right)=4\)=>9-3x+10x-2=4=>7x+7=4=>7x=-3=>x=-3/7c: \(\Leftrightarrow-3\left(4x+1\right)=2\left(4x-1\right)-6x-8\)=>\(-12x-3=8x-2-6x-8=2x-10\)=>-14x=-7=>x=1/2d: \(\Leftrightarrow\dfrac{5-x}{4x\left(x-2\right)}+\dfrac{7}{8x}=\dfrac{x-1}{2x\left(x-2\right)}+\dfrac{1}{8\left(x-2\right)}\)\(\Leftrightarrow2\left(5-x\right)+7\left(x-2\right)=4\left(x-1\right)+x\)=>\(10-2x+7x-14=4x-4+x=5x-4\)=>5x-4=5x-4(luôn đúng)=>S=R\{0;2}e: \(\Leftrightarrow x^3+1-x^3+1=\dfrac{3}{x}\)=>\(2x=3\)=>x=3/2