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★彡✿ทợท彡★ · Accepted Answer

$\left(\dfrac{x}{2}-\dfrac{3}{2}\right)\cdot\left(3x-\dfrac{1}{5}\right)=0$$\Rightarrow$ $\left(\dfrac{x}{2}-\dfrac{3}{2}\right)$ Hoặc $\left(3x-\dfrac{1}{5}\right)$ = 0+) $\dfrac{x}{2}-\dfrac{3}{2}=0$ $\Rightarrow$ $\dfrac{x}{2}=0+\dfrac{3}{2}$ $\Rightarrow$ $\dfrac{x}{2}=\dfrac{3}{2}$ $\Rightarrow$ $x=3$+) $3x-\dfrac{1}{5}=0$$\Rightarrow$ $3x=\dfrac{1}{5}$$\Rightarrow$  $x=\dfrac{1}{5}\div3$$\Rightarrow$ $x=\dfrac{1}{5}\cdot\dfrac{1}{3}=\dfrac{1}{15}$$\Rightarrow$ $x$ $\in$ {$3;\dfrac{1}{15}$}Vậy chọn B Câu trả lời: $\left(\dfrac{x}{2}-\dfrac{3}{2}\right)\cdot\left(3x-\dfrac{1}{5}\right)=0$$\Rightarrow$ $\left(\dfrac{x}{2}-\dfrac{3}{2}\right)$ Hoặc $\left(3x-\dfrac{1}{5}\right)$ = 0+) $\dfrac{x}{2}-\dfrac{3}{2}=0$ $\Rightarrow$ $\dfrac{x}{2}=0+\dfrac{3}{2}$ $\Rightarrow$ $\dfrac{x}{2}=\dfrac{3}{2}$ $\Rightarrow$ $x=3$+) $3x-\dfrac{1}{5}=0$$\Rightarrow$ $3x=\dfrac{1}{5}$$\Rightarrow$  $x=\dfrac{1}{5}\div3$$\Rightarrow$ $x=\dfrac{1}{5}\cdot\dfrac{1}{3}=\dfrac{1}{15}$$\Rightarrow$ $x$ $\in$ {$3;\dfrac{1}{15}$}Vậy chọn B

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