Câu 11: C
Câu 12:
\(\overrightarrow{AB}\cdot\overrightarrow{BC}=-\overrightarrow{BA}\cdot\overrightarrow{BC}\)
\(=-BA\cdot BC\cdot cosABC=-a^2\cdot cos60=-\dfrac{a^2}{2}\)
=>Chọn D
Câu 1:
a: C={x\(\in\)R|x>=1}
=>C=[1;+\(\infty\))
=>1\(\in C\)
D={x\(\in\)R|x>1}
=>D=(1;+\(\infty\))
=>1\(\notin\)D
=>Đúng
b: C=[1;+\(\infty\)); D=(1;+\(\infty\))
=>C\(\cup\)D=[1;+\(\infty\))
=>Đúng
c: E={x\(\in\)R||x|<5}
=>E=[-5;5]
mà D=(1;+\(\infty\))
nên D\(\cap\)E=(1;5]
=>Sai
d: C=[1;+\(\infty\)); D=(1;+\(\infty\))
=>C\(\cap\)D=(1;+\(\infty\))
\(E\cup C_R\left(C\cap D\right)\)
=[-5;5]\(\cup\)[R\(1;+\(\infty\))]
=[-5;5]\(\cup\)(-\(\infty\);1]
=(-\(\infty\);5]
=>Đúng