ĐKXĐ: \(x\ge-5\)
\(\Leftrightarrow\sqrt{4\left(x+5\right)}-3\sqrt{x+5}+\frac{4}{3}\sqrt{9\left(x+5\right)}=6\)
\(\Leftrightarrow2\sqrt{x+5}-3\sqrt{x+5}+4\sqrt{x+5}=6\)
\(\Leftrightarrow3\sqrt{x+5}=6\)
\(\Leftrightarrow\sqrt{x+5}=2\)
\(\Leftrightarrow x+5=4\Rightarrow x=-1\)
giải phương trình : \(\sqrt{4x+20}-3\sqrt{5+x}=6-\dfrac{4}{3}\sqrt{9x+45}\)
\(\sqrt{4x+20}-3\sqrt{5+x}+\dfrac{4}{3}\sqrt{9x+45}=6\)
\(\sqrt{4x-20}+3\sqrt{\frac{x-5}{9}}-\frac{1}{3}\sqrt{9x-45}=0\)
a,\(\sqrt{x^2-6x+9}=3\) b,\(\sqrt{4x+20}+\sqrt{x+5}-\dfrac{1}{3}\sqrt{9x+45}=4\)
tìm x
1. 4x-\(\sqrt{9x^2+6x+1}\)=0
2. \(\sqrt{4x}+20-3\sqrt{5+x}+\dfrac{4}{3}\sqrt{9x+45}=0\)
3. \(\sqrt{x^2}+x+1=x+2\)
4. \(\sqrt{6x^2}+2-\sqrt{3x^2}=\sqrt{26}-\sqrt{13}\)
5. \(\dfrac{\sqrt{x}-2}{\sqrt{x}-4}=\dfrac{\sqrt{x}-6}{\sqrt{x}-7}\)
6. \(\sqrt{4x^2-4x+1}=3\)
giải từng bước ra cho mik nha,thank mn
giải phương trình
a, \(\sqrt{4x-20}+3\sqrt{\dfrac{x-5}{9}}-\dfrac{1}{3}\sqrt{9x-45}=4\)
b, \(2x-x^2+\sqrt{6x^2-12x+7}=0\)
c, \(\dfrac{9x-7}{\sqrt{7x+5}}=\sqrt{7x+5}\)
Giải phương trình
\(a.\dfrac{3}{4}\sqrt{4x}-\sqrt{4x}+5=\dfrac{1}{4}\sqrt{4x}\)
\(b.\sqrt{3-x}-\sqrt{27-9x}+1,25.\sqrt{48-16x}=6\)
\(c.\dfrac{5\sqrt{x}-2}{8\sqrt{x}+2,5}=\dfrac{2}{7}\)
\(d.\sqrt{9x^2+12x+4}=4\)
Bài 1: Rút gọn biểu thức
a, ( \(\sqrt{8}-5\sqrt{2}+\sqrt{20}\) ). \(\sqrt{5}\)- ( \(3.\sqrt{\frac{1}{10}}+10\) )
b,\(\sqrt{2+\sqrt{3}}+\sqrt{2-\sqrt{3}}\)
Bài 2: Giải phương trình: \(\sqrt{4x+20}-3\sqrt{5+x}+\frac{4}{3}\sqrt{9x+45}=6\)
Bài 3: Cho biểu thức A= (\(\frac{1}{\sqrt{x}-1}-\frac{1}{\sqrt{x}}\)) : (\(\frac{\sqrt{x}+1}{\sqrt{x}-2}-\frac{\sqrt{x}+2}{\sqrt{x}-1}\) )
a, Tìm x để A xác định
b, Rút gọn A
c, Tìm x để A = \(\frac{1}{6}\)
Tìm x :
a, \(\sqrt{x^2-2x}=\sqrt{2-3x}\)
b, \(\sqrt{x-3}-2\sqrt{x^2-9}=0\)
c, \(\sqrt{4x-20}+\sqrt{x-5}-\frac{1}{3}\sqrt{9x-45}=4\)
d, \(\frac{1}{2}\sqrt{x-1}-\frac{3}{2}\sqrt{9x-9}+24\sqrt{\frac{x-1}{64}}=-17\)
e, \(\sqrt{9x^2+18}+2\sqrt{x^2+2}-\sqrt{25x^2+50}+3=0\)
f, \(\sqrt{x^2-4}-x+2=0\)