Question

giải phương trình

\(\frac{5x-2}{2-2x}\) + \(\frac{2x-1}{2}\) = 1 - \(\frac{x^2+x-3}{1-x}\)

\(\frac{5-2x}{3}\) + \(\frac{\left[x-1\right]\left[x+1\right]}{3x-1}\) = \(\frac{\left[x+2\right]\left[1-3x\right]}{9x-3}\)

giúp mình với được không ạ mình đang cần gấp

Answer 1

\(\Leftrightarrow\frac{5-2x}{3\left(3x-1\right)}+\frac{3\left(x^2-1\right)}{3\left(3x-1\right)}-\frac{\left(x+2\right)\left(1-3x\right)}{3\left(3x-1\right)}=0\)

\(\Rightarrow5-2x+3x^2-3-x+3x^2-2+6x=0\Leftrightarrow6x^2+3x=0\Leftrightarrow3x\left(2x+1\right)=0\Rightarrow\left[{}\begin{matrix}x=0\\x=-\frac{1}{2}\end{matrix}\right.\)

Answer 2

\(\Leftrightarrow-\frac{5x-2}{2\left(x-1\right)}+\frac{\left(2x-1\right)\left(x-1\right)}{2\left(x-1\right)}=\frac{1-x-x^2-x+3}{1-x}\Leftrightarrow\frac{2x^2-8x+3}{2\left(x-1\right)}=\frac{x^2+2x-4}{x-1}\)

\(\Rightarrow2x^2-8x+3=2x^2+4x-8\)\(\Leftrightarrow-8x+3=4x-8\Leftrightarrow-12x=-12\Rightarrow x=1\)