a: \(\frac{9x-0,7}{4}\) - \(\frac{5x-1,5}{7}\) = \(\frac{7x-1,1}{3}\) - \(\frac{5\left[0,4-2x\right]}{6}\)
b: \(\frac{3x-1}{x-1}\) - \(\frac{2x+5}{x+3}\) =1 - \(\frac{4}{\left[x-1\right]\left[x+3\right]}\)
c: \(\frac{3}{4\left[x-5\right]}\)+ \(\frac{15}{50-2x^2}\) = - \(\frac{7}{6\left[x+5\right]}\)
giả phương trình
giúp mình nhanh với ạ mình đang cần gấp
\(b,\frac{3x-1}{x-1}-\frac{2x+5}{x+3}=1-\frac{4}{\left(x-1\right)\left(x+3\right)}\) \(\left(Đkxđ:\left\{{}\begin{matrix}x\ne1\\x\ne-3\end{matrix}\right.\right)\)
\(\Leftrightarrow\frac{3x-1}{x-1}-\frac{2x+5}{x+3}+\frac{4}{\left(x-1\right)\left(x+3\right)}=1\)
\(\Leftrightarrow\frac{\left(3x-1\right)\left(x+3\right)}{\left(x-1\right)\left(x+3\right)}-\frac{\left(2x+5\right)\left(x-1\right)}{\left(x-1\right)\left(x+3\right)}+\frac{4}{\left(x-1\right)\left(x+3\right)}=\frac{\left(x-1\right)\left(x+3\right)}{\left(x-1\right)\left(x+3\right)}\)
\(\Leftrightarrow\left(3x^2+8x-3\right)-\left(2x^2+3x-5\right)+4=x^2+2x-3\)
\(\Leftrightarrow x^2+5x+6=x^2+2x-3\)
\(\Leftrightarrow9=-3x\)
\(\Leftrightarrow x=-3\left(ktmđk\right)\)
\(\Leftrightarrow Ptvn\)