\(\Leftrightarrow3\left(28x-4\right)=\dfrac{1}{3}\left(3+104x\right)+1-x\)
=>84x-12=1+104/3x+1-x
=>84x-12=101/3x+2
=>151/3x=14
hay x=151/42
Giải các phương trình :
a) \(x\left(2x-9\right)=3x\left(x-5\right)\)
b) \(0,5x\left(x-3\right)=\left(x-3\right)\left(1,5x-1\right)\)
c) \(3x-15=2x\left(x-5\right)\)
d) \(\dfrac{3}{7}x-1=\dfrac{1}{7}x\left(3x-7\right)\)
bài 1 : Giải cac phuong trinh sau
a, \(\dfrac{x-3}{5}=6-\dfrac{1-2x}{3}\)
b, \(\dfrac{3x-2}{6}-5=\dfrac{3-2\left(x+7\right)}{4}\)
c, \(2\left(x+\dfrac{3}{5}\right)=5-\left(\dfrac{13}{5}+x\right)\)
d, \(\dfrac{5\left(x-1\right)+2}{6}-\dfrac{7x-1}{4}=\dfrac{2\left(2x+1\right)}{7}-5\)
e, \(\dfrac{x-1}{2}+\dfrac{x-1}{4}=1-\dfrac{2\left(x-1\right)}{3}\)
g, \(\dfrac{2-x}{2001}-1=\dfrac{1-x}{2002}-\dfrac{x}{2003}\)
Các bạn ơi ! giúp mik với !!! chiều nay học roi
giải phương trình sau
a) \(\dfrac{\left(2x+1\right)^2}{5}-\dfrac{\left(x-1\right)^2}{3}=\dfrac{7x^2-14x-5}{15}\)
1, \(\dfrac{\left(2x-3\right)\cdot\left(2x+3\right)}{8}=\dfrac{\left(x-4\right)^2}{6}+\dfrac{\left(x-2\right)^2}{3}\)
2, \(x+2-\dfrac{2x-\dfrac{2x-5}{6}}{15}=\dfrac{7x-\dfrac{x-3}{2}}{5}\)
3, \(1-\dfrac{x-\dfrac{1+x}{3}}{3}=\dfrac{x}{2}-\dfrac{2x-\dfrac{10-7}{3}}{2}\)
4, \(\dfrac{x+1}{99}+\dfrac{x+3}{97}+\dfrac{x+5}{95}=\dfrac{x+7}{93}+\dfrac{9+x}{91}+\dfrac{x+11}{89}\)
Giải các phương trình sau :
a) \(\left(4x-10\right)\left(24+5x\right)=0\)
b) \(\left(3,5-7x\right)\left(0,1x+2,3\right)=0\)
c) \(\left(3x-2\right)\left(\dfrac{2\left(x+3\right)}{7}-\dfrac{4x-3}{5}\right)=0\)
d) \(\left(3,3-11x\right)\left(\dfrac{7x+2}{5}+\dfrac{2\left(1-3x\right)}{3}\right)=0\)
giải pt:
\(\dfrac{3\left(5-x\right)}{4}-2=\dfrac{7x}{3}-5\left(x-7\right)\)
giải pt
a)\(\left(x+1\right)^2-1+x^2=\left(1-x\right)\left(x+3\right)\)
b)\(x^4+x^3+x+1=0\)
c)\(\dfrac{6x+1}{x^2-7x+10}+\dfrac{5}{x-2}=\dfrac{3}{x-5}\)
giải các phương trình:
a)(x2+x+1)2-2x2-2x=5
b)\(\dfrac{1}{\left(x-1\right)\left(x-3\right)}\)+x2-4x+5=0
Giải pt:
a, \(\dfrac{1}{27}.\left(x-3\right)^2-\dfrac{1}{125}.\left(x-5\right)^3=0\)
b, \(125x^3-\left(2x+1\right)^3-\left(3x-1\right)^3=0\)
c, \(\left(x-3\right)^3+\left(x+1\right)^3=8.\left(x-1\right)^3\)
