a, ⇔ x4 - 2x3 + 4x3 - 8x2 + 4x2 - 8x + 3x - 6 = 0
⇔ (x - 2)(x3 + 4x2 + 4x + 3) = 0
⇔ (x - 2)(x3 + 3x2 + x2 + 3x + x + 3) = 0
⇔ (x - 2)(x + 3)(x2 + x + 1) = 0 mà x2 + x + 1 > 0 ∀ x
⇔ \(\left\{{}\begin{matrix}x-2=0\\x+3=0\end{matrix}\right.\)
⇔ \(\left\{{}\begin{matrix}x=2\\x=-3\end{matrix}\right.\)
Vậy tập nghiệm phương trình S = {2; -3}
Giải các phương trình
1,\(3x-1=0\\\) 4, \(\dfrac{x}{3}-\dfrac{x}{5}=4\)
2, \(2-x=3x+1\) 5, \(\dfrac{x-1}{4}+\dfrac{2x+1}{6}=\dfrac{3}{2}\)
3, \(2\left(x-2\right)-1=5x\)
giải phương trình 1)\(\dfrac{1-6x}{x-2}+\dfrac{9x+4}{x+2}=\dfrac{x\left(3x-2\right)+1}{x^2-4}\)2) \(\dfrac{3x+2}{3x-2}-\dfrac{6}{2+3x}=\dfrac{9x^2}{9x^2-4}\)3) \(\dfrac{x+5}{3x-6}-\dfrac{1}{2}=\dfrac{2x-3}{2x-4}\)4) \(\dfrac{x-1}{x}+\dfrac{1}{x+1}=\dfrac{2x-1}{2x^2+2}\)5) \(\dfrac{2}{x+1}+\dfrac{3x+1}{x+1}=\dfrac{1}{\left(x+1\right)\left(x-2\right)}\)
Giải phương trình
1, \(\dfrac{1-6x}{x-2}+\dfrac{9x+4}{x+2}=\dfrac{x\left(3x-2\right)+1}{x^2-4}\)
2, \(\dfrac{3x+2}{3x-2}-\dfrac{6}{2-3x}=\dfrac{9x^2}{9x^2-4}\)3, \(\dfrac{x-1}{x}+\dfrac{1}{x+1}=\dfrac{2x-1}{2x^2+2}\)4, \(\dfrac{2}{x+1}+\dfrac{3x+1}{x+1}=\dfrac{1}{\left(x+1\right)\left(x-2\right)}\)5, \(\dfrac{x+5}{3x-6}-\dfrac{1}{2}=\dfrac{2x-3}{2x-4}\)
Giải các phương trình
a)3x-2=2x-3 c)11x+42-2x=100-9x-22
b)2x+3=5x+9 d)2x-(3-5x)=4(x+3)
e)\(\dfrac{3x+2}{2}-\dfrac{3x+1}{6}=\dfrac{5}{3}+2x\)
f)\(\dfrac{x+4}{5}-x+4=\dfrac{x}{3}-\dfrac{x-2}{2}\)
g)(2x+1)(x-1)=0
h)(x+\(\dfrac{2}{3}\))(x-\(\dfrac{1}{2}\))=0
i)(3x-1)(2x-3)(2x-3)(x+5)=0
k)3x-15=2x(x-5)
m)\(\left|x-2\right|=3\)
n)\(\left|x+1\right|=\left|2x+3\right|\)
j)\(\dfrac{7x-3}{x-1}=\dfrac{2}{3}\)
đ)\(\dfrac{2\left(3-7x\right)}{1+x}=\dfrac{1}{2}\)
y)\(\dfrac{x+5}{x-5}-\dfrac{x-5}{x+5}=\dfrac{20}{x^2-25}\)
\(\dfrac{1}{x-1}+\dfrac{2}{x+1}=\dfrac{x}{x^2-1}\)
Giải các phương trình
1, \(\dfrac{1}{x}-\dfrac{2}{x+1}=\dfrac{3}{x^2+x}\)
2, \(\dfrac{x+2}{x-2}-\dfrac{1}{x}=\dfrac{2}{x\left(x-2\right)}\)
3, \(\dfrac{x-2}{x+2}-\dfrac{3}{x-2}=\dfrac{2\left(x-11\right)}{x^2-4}\)
giải các phương trình chứa ẩn
a) \(\dfrac{2\cdot\left(x^2+x+6\right)}{x^3-8}+\dfrac{2}{2-x}=\dfrac{3}{x^2+2x+4}\)
b) \(\dfrac{6}{x^3+1}-\dfrac{1-x}{x^2-x+1}=\dfrac{5}{x+1}\)
c) \(\dfrac{1}{x^2+3x+2}-\dfrac{3}{x^2-x-2}=\dfrac{-1}{x^2-4}\)
Giải phương trình:
a) \(\dfrac{2x^2-x-1}{2}-3x^2+x+4=\left(5-x\right)\left(2x+4\right)\)
b) \(\dfrac{\left(2x-5\right)\left(3x+7\right)}{4}+2x-1=\dfrac{\left(x-1\right)\left(2x+4\right)}{2}+1\)
c) 8x3 - 1 = 8x2 + 4x + 2
d) (x2 + x + 1)(x2 - x + 1) = x6 - 1
e) (x3 + 2x)(x2 + 4) = (x4 + 6x2 + 8)(3 - 2x)
f) \(\dfrac{x+97}{125}+\dfrac{x-63}{35}=\dfrac{x-7}{21}+\dfrac{x-27}{49}\)
Giúp mình với!!! Mình cần gấp!!! Câu nào cũng được nhe!!!
giải phương trình bằng cách đưa về dạng ax+b=0
\(\dfrac{5\left(x-1\right)+2}{6}-\dfrac{7x-1}{4}=\dfrac{2\left(2x+1\right)}{7}-5\)
giải phương trình,giúp với ạ
\(\dfrac{x+1}{4}-\dfrac{5+2x}{8}=\dfrac{3-4x}{2}\)
\(\dfrac{4-3x}{5}-\dfrac{4-x}{10}=\dfrac{x+2}{2}\)