Làm nốt phần b)
\(\left(\sqrt{3}-1\right)x-x+4-2\sqrt{3}=0\)
\(\Leftrightarrow x\left(\sqrt{3}-2\right)=2\sqrt{3}-4\)
\(\Leftrightarrow x\left(\sqrt{3}-2\right)=2\left(\sqrt{3}-2\right)\)
\(\Leftrightarrow x=2\)
KL.........
Giải:
a) \(\left(\sqrt{3}-1\right)x=2\left(\sqrt{3}+1\right)x-3\sqrt{3}\)
\(\Leftrightarrow\left(\sqrt{3}-1\right)x-2\left(\sqrt{3}+1\right)x=-3\sqrt{3}\)
\(\Leftrightarrow x\left(\sqrt{3}-1-2\sqrt{3}-2\right)=-3\sqrt{3}\)
\(\Leftrightarrow x\left(-3-\sqrt{3}\right)=-3\sqrt{3}\)
\(\Leftrightarrow x=\dfrac{-3\sqrt{3}}{-3-\sqrt{3}}\)
\(\Leftrightarrow x=\dfrac{-\left(3\sqrt{3}\right)}{-\left(3+\sqrt{3}\right)}\)
\(\Leftrightarrow x=\dfrac{-\sqrt{3}.3}{-\sqrt{3}\left(\sqrt{3}+1\right)}\)
\(\Leftrightarrow x=\dfrac{3}{\sqrt{3}+1}\)
Vậy ... (Làm bừa, bạn xem ý thôi nhé)
b) Nhờ các anh chị làm ạ
