\(\left\{{}\begin{matrix}\sqrt[3]{x-y}=\sqrt{x-y}\\x+y=\sqrt{x+y+2}\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}\sqrt[3]{x-y}\left(1-\sqrt[6]{x-y}\right)=0\\x+y=\sqrt{x+y+2}\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}\left[{}\begin{matrix}x=y\\x=1+y\end{matrix}\right.\\x+y=\sqrt{x+y+2}\end{matrix}\right.\)
Rồi thế vô là giải tiếp sẽ ra