Question

\(\dfrac{3\sqrt{2}-2}{3-\sqrt{2}}\)-\(\dfrac{2+3\sqrt{2}}{\sqrt{2}}\)

Answer 1

\(=\dfrac{3\cdot\sqrt{2}-\sqrt{2}\cdot\sqrt{2}}{3-\sqrt{2}}+\dfrac{\sqrt{2}\cdot\sqrt{2}+3\cdot\sqrt{2}}{\sqrt{2}}\)

\(=\dfrac{\sqrt{2}\left(3-\sqrt{2}\right)}{3-\sqrt{2}}-\dfrac{\sqrt{2}\left(3+\sqrt{2}\right)}{\sqrt{2}}\)

\(=\sqrt{2}-3-\sqrt{2}=-3\)