Question

\(\dfrac{14}{3x-12}-\dfrac{2+x}{x-4}=\dfrac{3}{8-2x}-\dfrac{5}{6}\)

Answer 1

ĐKXĐ: x\(\ne\)4

\(\Leftrightarrow\dfrac{14}{3\left(x-4\right)}-\dfrac{x+2}{x-4}=\dfrac{3}{2\left(4-x\right)}-\dfrac{5}{6}\)

\(\Leftrightarrow\dfrac{14}{3\left(x-4\right)}-\dfrac{x+2}{x-4}+\dfrac{3}{2\left(x-4\right)}=-\dfrac{5}{6}\)

\(\Rightarrow14\cdot2-6\cdot\left(x+2\right)+3\cdot3=-5\left(x-4\right)\)

\(\Leftrightarrow28-6x-12+9=-5x+20\)

\(\Leftrightarrow25-6x=-5x+20\Leftrightarrow-6x+5x=20-25\Leftrightarrow-x=-5\Leftrightarrow x=5\left(TM\right)\)Vậy...