Question

\(Cho\frac{2x+y+z+t}{x}\text{=}\frac{x+2y+z+t}{y}\text{=}\frac{x+y+2z+t}{z}\text{=}\frac{x+y+z+2t}{t}\)

Tính S=\(\text{(\frac{x+y}{z+t})^{2013}+\text{(\frac{y+z}{x+t})^{2014}+\text{(\frac{z+t}{x+y})^{2015}}}}+\text{(\frac{x+t}{y+z})}^{2016}\)