Ta có: \(\frac{x+17}{2001}+\frac{x+3}{2015}+\frac{x+5}{2013}=-3\)
\(\Leftrightarrow\frac{x+17}{2001}+\frac{x+3}{2015}+\frac{x+5}{2013}+3=0\)
\(\Leftrightarrow\frac{x+17}{2001}+1+\frac{x+3}{2015}+1+\frac{x+5}{2013}+1=0\)
\(\Leftrightarrow\frac{x+17+2001}{2001}+\frac{x+3+2015}{2015}+\frac{x+5+2013}{2013}=0\)
\(\Leftrightarrow\frac{x+2018}{2001}+\frac{x+2018}{2015}+\frac{x+2018}{2013}=0\)
\(\Leftrightarrow\left(x+2018\right)\left(\frac{1}{2001}+\frac{1}{2015}+\frac{1}{2013}\right)=0\)
mà \(\frac{1}{2001}+\frac{1}{2015}+\frac{1}{2013}\ne0\)
nên x+2018=0
hay x=-2018
Vậy: x=-2018