Tam giác AEC có góc AEC = \(90^0\)
=> \(AC^2=AE^2+EC^2\)
=>\(EC^2=AC^2-AE^2\)
=>\(EC^2=5^2-4^2\)
=>\(EC=\sqrt{9}=3\left(m\right)\)
Có EB + EC = BC
=>EB = BC - EC
=>EB = 9 - 3
=> EB = 6 (m)
Tam giác AEB có góc AEB = \(90^0\)
=>\(AB^2=AE^2+EB^2\)
=>\(AB^2=4^2+6^2\)
=>\(AB^2=16+36\)
=>\(AB^2=52\)
=>\(AB=\sqrt{52}=2\sqrt{13}\) (m)