Question

Bài1: Tìm x

a) \(x+\dfrac{5}{3}=\dfrac{7}{12}\)

b) \(\dfrac{7}{4}-x=\dfrac{5}{6}\)

c) \(\dfrac{3}{5}+x=\dfrac{1}{2}+\dfrac{3}{4}\)

d) \(\dfrac{-3}{8}\le x< \dfrac{1}{2}+\dfrac{3}{4}\)

 

Answer 1

`a, x = 7/12 - 5/3`

`x = -13/12`

`b, x = 7/4 - 5/6`

`x=  11/12`

`c, 3/5 + x = 5/4`

`x = 5/4 -3/5`

`x = 13/20`

`d, -3/8 <= x < 1/2 + 3/4`

`-3/8 <= x < 5/4`.

Answer 2

\(a,x+\dfrac{5}{3}=\dfrac{7}{12}\)

\(x=\dfrac{7}{12}-\dfrac{5}{3}\)

\(x=\dfrac{7-20}{12}=-\dfrac{13}{12}\)

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\(b,\dfrac{7}{4}-x=\dfrac{5}{6}\)

\(x=\dfrac{7}{4}-\dfrac{5}{6}\)

\(x=\dfrac{21-10}{12}=\dfrac{11}{12}\)

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\(c,\dfrac{3}{5}+x=\dfrac{1}{2}+\dfrac{3}{4}\)

\(\dfrac{3}{5}+x=\dfrac{5}{4}\)

\(x=\dfrac{5}{4}-\dfrac{3}{5}\)

\(x=\dfrac{25-12}{20}=\dfrac{13}{20}\)

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\(d,-\dfrac{3}{8}\le x< \dfrac{1}{2}+\dfrac{3}{4}\)

\(-\dfrac{3}{8}\le x< \dfrac{10}{8}\)