Question

Bài 2: Phân tích các đa thức sau thành nhân tử bằng phương pháp dùng hằng đẳng thức

a)x²-4x+4        b)4x²+4x+1         c)16x²-9y²

d)16-(x+3)²      e)4x²-(3x-1)²        f)x³-y³

g)27+x³             h)x³+6x²+12x+8        i)1-3x+3x²-x³

^{giúp mình cần gấp ,mn ơi}

Answer 1

a) \(=\left(x-2\right)^2\)

b) \(=\left(2x+1\right)^2\)

c) \(=\left(4x-3y\right)\left(4x+3y\right)\)

d) \(=\left(4-x-3\right)\left(4+x+3\right)=\left(1-x\right)\left(x+7\right)\)

e) \(=\left(2x-3x+1\right)\left(2x+3x-1\right)=\left(1-x\right)\left(5x-1\right)\)

f) \(=\left(x-y\right)\left(x^2+xy+y^2\right)\)

g) \(=\left(x+3\right)\left(x^2-3x+9\right)\)

h) \(=\left(x+2\right)^3\)

i) \(=\left(1-x\right)^3\)

Answer 2

Answer 3

a/ $=(x-2)^2$

b/ $=(2x+1)^2$

c/ $=(4x-3y)(4x+3y)$

d/ $=(1-x)(x+7)$

e/ $=(-x+1)(5x-1)$

f/ $=(x-y)(x^2+xy+y^2)$

g/ $=(3+x)(9-3x+x^2)$

h/ $=(x+2)^3$

i/ $=(1-x)^3$

Answer 4

a) \(= ( x - 2 )^2\)

b) \(= ( 2x + 1)^2\)

c) \(= ( 4x - 3y ) ( 4x + 3y )\)

d) \(= ( 4 - x - 3 ) ( 4 + x + 3 ) = ( 1 - x ) ( x + 7 )\)

e) \(= ( 2x - 3x + 1 ) ( 2x + 3x - 1 ) = ( 1 - x ) ( 5x - 1 )\)

f) \(= ( x - y ) ( x^2 + xy + y^2 )\)

g) \(= ( x + 3 ) ( x^2 - 3x + 9 )\)

h) \(= ( x + 2 )^3\)

i) \(= ( 1 - x )^3\)