Question

Bài 2: Giải phương trình

(2x-1)(x+2)=(x+2)(x+3)

Answer 1

\(\Leftrightarrow\left(x+2\right)\left(2x-1-x-3\right)=0\)

=>(x+2)(x-4)=0

=>x=-2 hoặc x=4

Answer 2

\(\left(2x-1\right)\left(x+2\right)=\left(x+2\right)\left(x+3\right)\)

\(\Leftrightarrow\left(2x-1\right)\left(x+2\right)-\left(x+2\right)\left(x+3\right)=0\)

\(\Leftrightarrow\left(x+2\right)\left(2x-1-x-3\right)=0\)

\(\Leftrightarrow\left(x+2\right)\left(x-4\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x=-2\\x=4\end{matrix}\right.\)

Vậy \(S=\left\{-2;4\right\}\)

Answer 3

=>(x+2)(x-4)=0

=>x=-2 hoặc x=4.