\(\frac{1}{3}\). \(\sqrt{72}\) - \(3\sqrt{35}\) - \(\frac{\sqrt{66}}{\sqrt{33}}\)
= \(\frac{1}{3}\). \(6\sqrt{2}\) - \(3\sqrt{35}\) - \(\sqrt{2}\)
= \(2\sqrt{2}\) - \(3\sqrt{35}\) - \(\sqrt{2}\)
= \(\sqrt{2}\) - \(3\sqrt{35}\)
Vậy được chưa bạn?
\(\frac{1}{3}\). \(\sqrt{72}\) - \(3\sqrt{35}\) - \(\frac{\sqrt{66}}{\sqrt{33}}\)
= \(\frac{1}{3}\). \(6\sqrt{2}\) - \(3\sqrt{35}\) - \(\sqrt{2}\)
= \(2\sqrt{2}\) - \(3\sqrt{35}\) - \(\sqrt{2}\)
= \(\sqrt{2}\) - \(3\sqrt{35}\)
Vậy được chưa bạn?
B1, P=(\(\frac{1-a\sqrt{a}}{1-\sqrt{ }a}+\sqrt{a})(\frac{1+a\sqrt{a}}{1+\sqrt{a}}-\sqrt{a})\)
a, rút gọn P
B2, P=(\(\frac{2\sqrt{x}}{\sqrt{x}+3}+\frac{\sqrt{x}}{\sqrt{x}-3}_{ }-\frac{3x+3}{x-9}):(\frac{2\sqrt{x}-2}{\sqrt{x}-3}-1)\)
a, Rút gọn P
a, P=\((\frac{1-a\sqrt{a}}{1-\sqrt{a}}+\sqrt{a})(\frac{1+a\sqrt{a}}{1+\sqrt{a}}-\sqrt{a}\))
Rút gọn P.
b, P=(\(\frac{2\sqrt{x}}{\sqrt{x}+3}+\frac{\sqrt{x}}{\sqrt{x}-3}-\frac{3x+3}{x-9}):(\frac{2\sqrt{x}-2}{\sqrt{x}-3}-1)\)
Rút gọn P
(Làm ơn giúp mk với..arigato cực cực super nhiều ạ...
rút gọn
a. A=\(\frac{1+\sqrt{5}}{\sqrt{2}+\sqrt{3+\sqrt{5}}}+\frac{1-\sqrt{5}}{\sqrt{2}-\sqrt{3-\sqrt{5}}}\)
b. B=\(\left(\frac{1-a\sqrt{a}}{1-\sqrt{a}}+\sqrt{a}\right)\left(\frac{1-\sqrt{a}}{1-a}\right)^2\)
Rút gọn
\(A=\left(\frac{\sqrt{x}-1}{3\sqrt{x}-1}-\frac{1}{3\sqrt{x}+1}+\frac{8\sqrt{x}}{9x-1}\right):\left(1-\frac{3\sqrt{x}-2}{3\sqrt{x}+1}\right)\)
\(B=\left(\frac{x-3\sqrt{x}}{x-9}-1\right):\left(\frac{9-x}{x+\sqrt{x}-6}+\frac{\sqrt{x}-3}{\sqrt{x}-2}-\frac{\sqrt{x}-2}{\sqrt{x}+3}\right)\)
1.Trục căn thức ở mẫu
\(\frac{\sqrt{a}-\sqrt{b}}{\sqrt{a}+\sqrt{b}}\)
2.Rút gọn
a,\(\frac{2}{\sqrt{3}-1}-\frac{2}{\sqrt{3}+1}\)
b,\(\frac{5+\sqrt{5}}{5-\sqrt{5}}+\frac{5-\sqrt{5}}{5+\sqrt{5}}\)
c,\(\frac{1}{\sqrt{5}-\sqrt{3}}-\frac{1}{\sqrt{3}-\sqrt{2}}-\frac{2}{\sqrt{5}+\sqrt{2}}\)
rút gọn:
\(\frac{1}{2\sqrt{1}+1\sqrt{2}}+\frac{1}{3\sqrt{2}+2\sqrt{3}}+\frac{1}{4\sqrt{3}+3\sqrt{4}}+....+\frac{1}{25\sqrt{24}+24\sqrt{25}}\)
Rút gọn biểu thức:
\(A=\frac{1}{\sqrt{1}-\sqrt{2}}-\frac{1}{\sqrt{2}-\sqrt{3}}+\frac{1}{\sqrt{3}-\sqrt{4}}-\frac{1}{\sqrt{4}-\sqrt{5}}\)
\(B=\left(\frac{5-\sqrt{5}}{\sqrt{5}}-2\right)\left(\frac{4}{1+\sqrt{5}}+4\right)\)
\(C=\left(\frac{3+2\sqrt{3}}{\sqrt{3}+2}+\frac{2+\sqrt{2}}{\sqrt{2}+1}\right):\left(1:\frac{1}{\sqrt{2}+\sqrt{3}}\right)\)
\(D=2\sqrt{50}-\frac{1}{\sqrt{2}-1}+4\sqrt{\frac{9}{2}}-\sqrt{3-2\sqrt{2}}\)
rút gọn \(\frac{1}{2-\sqrt{5}}+\frac{2}{\sqrt{5}+\sqrt{3}}:\frac{1}{\sqrt{21-12\sqrt{3}}}\)
\(\frac{5\sqrt{3}}{\sqrt{3}-\sqrt{5}-\sqrt{3}}-\frac{5\sqrt{3}}{\sqrt{3-\sqrt{5}}+\sqrt{3}}\)
Rút gọn:
A=\(\frac{\sqrt{3}-\sqrt{6}}{1-\sqrt{2}}-\frac{2+\sqrt{8}}{1+\sqrt{2}}\)
B= \(\frac{1}{3-\sqrt{5}}-\frac{1}{\sqrt{5}+1}\)
C=( \(\frac{a\sqrt{a}-1}{a-\sqrt{a}}-\frac{a\sqrt{a}+1}{a+\sqrt{a}}\)):\(\frac{a+2}{a-2}\)(a>0;a#1)