a) Ta có: \(\frac{3x}{x-2}-\frac{x}{x-5}+\frac{2x^2}{7x-10-x^2}=0\)
\(\Leftrightarrow\frac{3x}{x-2}-\frac{x}{x-5}-\frac{2x^2}{x^2-7x+10}=0\)
\(\Leftrightarrow\frac{3x\left(x-5\right)}{\left(x-2\right)\left(x-5\right)}-\frac{x\left(x-2\right)}{\left(x-5\right)\left(x-2\right)}-\frac{2x^2}{\left(x-5\right)\left(x-2\right)}=0\)
\(\Leftrightarrow3x^2-15x-x^2+2x-2x^2=0\)
\(\Leftrightarrow-13x=0\)
\(\Leftrightarrow x=0\)
Vậy: x=0
c) Ta có: \(\left(2x-1\right)^2-\left(2x+1\right)^2=4\left(x-3\right)\)
\(\Leftrightarrow\left(2x-1+2x+1\right)\left(2x-1-2x-1\right)-4\left(x-3\right)=0\)
\(\Leftrightarrow-8x-4x+12=0\)
\(\Leftrightarrow-12x+12=0\)
\(\Leftrightarrow x=\frac{-12}{-12}=1\)
Vậy: x=1