Question

b) [(4x+28).3+55]:5=35   

Answer 1

`@` `\text {Ans}`

`\downarrow`

`b)`

\([(4x+28).3+55] \div 5=35\)

`=> (4x + 28) * 3 + 55 = 35 * 5`

`=> (4x + 28)*3 + 55 = 175`

`=> (4x + 28)*3 = 175 - 55`

`=> (4x + 28)*3 =120`

`=> 4x + 28 = 120 \div 3`

`=> 4x + 28 = 40`

`=> 4x = 40 - 28`

`=> 4x = 12`

`=> x = 12 \div 4`

`=>x = 3`

Vậy, `x = 3.`

Answer 2

=>[12x+84+55]=175

=>12x=175-84-55=120-84=36

=>x=36/12=3

Answer 3

<=>[12x+84+55]:5=35

<=>[12x+139]:5=35

<=>12x+139=35.5

<=>12x=175-139

<=>x=3