b: =căn 10-3+4-căn 10=1
a: \(=\sqrt{11-4\sqrt{6}+\sqrt{15}}\)
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a) 11+6\(\sqrt{2}\) = \(\left(3+\sqrt{2}\right)^2\)
b) 8-2\(\sqrt{7}\)=\(\left(\sqrt{7}-1\right)^2\)
c)\(\sqrt{11+6\sqrt{2}}=\sqrt{11-6\sqrt{2}}=6\)
d) \(\sqrt{8-2\sqrt{7}}-\sqrt{8+2\sqrt{7}}=-2\)
\(\sqrt{\left(11-6\sqrt{2}\right)^2}+\sqrt{\left(11+6\sqrt{2}\right)^2}\)
\(\sqrt{\left(10-4\sqrt{6}\right)^2}-\sqrt{\left(10+4\sqrt{6}\right)^2}\)
\(\sqrt{\left(4-\sqrt{5}\right)^2}+\sqrt{\left(1-\sqrt{5}\right)^2}\)
\(\sqrt{\left(7+\sqrt{2}\right)^2}-\sqrt{\left(1-\sqrt{2}\right)^2}\)
RÚT GỌN BIỂU THỨC
A= \(\left(2+\dfrac{5-2\sqrt{5}}{2-\sqrt{5}}\right)\)\(\left(2+\dfrac{5+3\sqrt{5}}{3+\sqrt{5}}\right)\)
B= \(\left(\dfrac{15}{\sqrt{6}+1}+\dfrac{4}{\sqrt{6}-2}-\dfrac{12}{3-\sqrt{6}}\right)\)\(\left(\sqrt{6}+11\right)\)
Tínha.left(sqrt{10}-sqrt{2}right)left(3+sqrt{5}right)sqrt{27-9sqrt{5}}b.sqrt{frac{3sqrt{3}-4}{2sqrt{3}+1}}-sqrt{frac{4+sqrt{3}}{5-2sqrt{3}}}c.frac{3-4sqrt{3}}{sqrt{6}-sqrt{2}-sqrt{5}}d.left(sqrt{11}-sqrt{3}right)left(sqrt{13-sqrt{6}+2sqrt{30-sqrt{45}}}+sqrt{11}-sqrt{10-sqrt{6}}right)e.frac{sqrt{4+sqrt{5}}+sqrt{4-sqrt{5}}}{sqrt{4}+sqrt{11}}-frac{sqrt{20-4sqrt{23}}}{sqrt{5+sqrt{2}}-sqrt{5-sqrt{2}}}
Đọc tiếp
\(Tính\)
\(a.\left(\sqrt{10}-\sqrt{2}\right)\left(3+\sqrt{5}\right)\sqrt{27-9\sqrt{5}}\)
\(b.\sqrt{\frac{3\sqrt{3}-4}{2\sqrt{3}+1}}-\sqrt{\frac{4+\sqrt{3}}{5-2\sqrt{3}}}\)
\(c.\frac{3-4\sqrt{3}}{\sqrt{6}-\sqrt{2}-\sqrt{5}}\)
\(d.\left(\sqrt{11}-\sqrt{3}\right)\left(\sqrt{13-\sqrt{6}+2\sqrt{30-\sqrt{45}}}+\sqrt{11}-\sqrt{10-\sqrt{6}}\right)\)
\(e.\frac{\sqrt{4+\sqrt{5}}+\sqrt{4-\sqrt{5}}}{\sqrt{4}+\sqrt{11}}-\frac{\sqrt{20-4\sqrt{23}}}{\sqrt{5+\sqrt{2}}-\sqrt{5-\sqrt{2}}}\)
TC
20 tháng 8 2021 lúc 21:02
Tính
a,\(\sqrt{4+\sqrt{15}}\)
b,\(\left(3-\sqrt{2}\right)\sqrt{11+6\sqrt{2}}\)
c,\(\left(\sqrt{5}+\sqrt{7}\right)\sqrt{12-2\sqrt{35}}\)
1) left(sqrt{6}-sqrt{8}right)left(sqrt{6}+sqrt{8}right).2)left(3-sqrt{5}right)left(3+sqrt{5}right)3)sqrt{7-4sqrt{3}}+sqrt{7+4sqrt{3}}4)sqrt{2sqrt{3}-4}+sqrt{2sqrt{3}+4}5)sqrt{4sqrt{6}+11}-sqrt{11-4sqrt{6}}6)sqrt{10+2sqrt{11}}-sqrt{10-2sqrt{11}}7)sqrt{5-2sqrt{7-2sqrt{6}}}AI ĐÓ TỐT BỤNG GIÚP MK ZỚI:((
Đọc tiếp
1) \(\left(\sqrt{6}-\sqrt{8}\right)\left(\sqrt{6}+\sqrt{8}\right).\)
2)\(\left(3-\sqrt{5}\right)\left(3+\sqrt{5}\right)\)
3)\(\sqrt{7-4\sqrt{3}}+\sqrt{7+4\sqrt{3}}\)
4)\(\sqrt{2\sqrt{3}-4}+\sqrt{2\sqrt{3}+4}\)
5)\(\sqrt{4\sqrt{6}+11}-\sqrt{11-4\sqrt{6}}\)
6)\(\sqrt{10+2\sqrt{11}}-\sqrt{10-2\sqrt{11}}\)
7)\(\sqrt{5-2\sqrt{7-2\sqrt{6}}}\)
AI ĐÓ TỐT BỤNG GIÚP MK ZỚI:((
Rút gọn
1) \(E=\left(\sqrt{11}-3\right)\left(\sqrt{13-\sqrt{6}+2\sqrt{30-\sqrt{54}}}+\sqrt{11}-\sqrt{10-\sqrt{6}}\right)\)
2) \(F=\frac{\left(\sqrt{3-\sqrt{5}}-1\right)\left(\sqrt{3-\sqrt{5}}\left(3-\sqrt{5}\right)+1\right)}{4-\sqrt{5}-\sqrt{3-\sqrt{5}}}+\sqrt{5}\)
thực hiện phép tínha)dfrac{3}{5}-dfrac{1}{2}sqrt{1dfrac{11}{25}}b)(5+2sqrt{6})(5-2sqrt{6})c)sqrt{left(2-sqrt{3}right)^2}+sqrt{4-2sqrt{3}}d)dfrac{left(xsqrt{y}+ysqrt{x}right)left(sqrt{x}-sqrt{y}right)}{sqrt{xy}}(với x,y0)
Đọc tiếp
thực hiện phép tính
a)\(\dfrac{3}{5}\)-\(\dfrac{1}{2}\)\(\sqrt{1\dfrac{11}{25}}\)
b)(5+2\(\sqrt{6}\))(5-2\(\sqrt{6}\))
c)\(\sqrt{\left(2-\sqrt{3}\right)^2}\)+\(\sqrt{4-2\sqrt{3}}\)
d)\(\dfrac{\left(x\sqrt{y}+y\sqrt{x}\right)\left(\sqrt{x}-\sqrt{y}\right)}{\sqrt{xy}}\)(với x,y>0)
a) \(A=\sqrt{8+2\sqrt{10+2\sqrt{5}}}+\sqrt{8-2\sqrt{10+2\sqrt{5}}}\)
b) \(B=\left(\frac{15}{\sqrt{6}+1}+\frac{4}{\sqrt{6}-2}+\frac{12}{3-\sqrt{6}}\right)\left(\sqrt{6}+11\right)\)
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