\(a,\dfrac{1}{2}+\dfrac{x-1}{3}=\dfrac{2x+1}{6}\\ \Leftrightarrow\dfrac{3}{6}+\dfrac{2\left(x-1\right)}{6}=\dfrac{2x+1}{6}\\ \Leftrightarrow3+2\left(x-1\right)=2x+1\\ \Leftrightarrow3+2x-2=2x+1\\ \Leftrightarrow2x+1=2x+1\)
Vậy pt có vô số nghiệm
\(b,\dfrac{x-1}{5}+x=\dfrac{x+1}{7}\\ \Leftrightarrow\dfrac{7\left(x-1\right)}{35}+\dfrac{35x}{35}=\dfrac{5\left(x+1\right)}{35}\\ \Leftrightarrow7\left(x-1\right)+35x=5\left(x+1\right)\\ \Leftrightarrow7x-7+35x=5x+5\\ \Leftrightarrow42x-7-5x-5=0\\ \Leftrightarrow37x-12=0\\ \Leftrightarrow x=\dfrac{12}{37}\)
Vậy pt có tập nghiệm \(S=\left\{\dfrac{12}{37}\right\}\)
a: =>3+2(x-1)=2x+1
=>2x-2+3=2x+1
=>2x+1=2x+1
=>0x=0(luôn đúng)
b: =>7(x-1)+35x=5(x+1)
=>42x-7-5x-5=0
=>37x=12
hay x=12/37
\(a,PT\Leftrightarrow\dfrac{3}{6}+\dfrac{2x-2}{6}=\dfrac{2x+1}{6}\)
\(\Leftrightarrow3+2x-2-2x-1=0\)
\(\Leftrightarrow0x=0\) (luôn đúng \(\forall x\))
Vậy phương trình có vô số nghiệm.
\(b,PT\Leftrightarrow\dfrac{7x-7}{35}+\dfrac{35x}{35}=\dfrac{5x+5}{35}\)
\(\Leftrightarrow7x-7+35x-5x-5=0\)
\(\Leftrightarrow37x=12\)
\(\Leftrightarrow x=\dfrac{12}{37}\)
Vậy: \(S=\left\{\dfrac{12}{37}\right\}\)