a) \(⇔-4x^2-4x+7x+7=0\)
\(⇔-4x(x+1)+7(x+1)=0\)
\(⇔(x+1)(-4x+7)=0\)
\(⇔\left[\begin{array}{} x+1=0\\ -4x+7=0 \end{array}\right.⇔\left[\begin{array}{} x=-1\\ x=\frac{7}{4} \end{array}\right.\)
b) \(⇔4x^2-8x+3x-6=0\)
\(⇔4x(x-2)+3(x-2)=0\)
\(⇔(x-2)(4x+3)=0\)
\(⇔\left[\begin{array}{} x-2=0\\ 4x+3=0 \end{array}\right.⇔\left[\begin{array}{} x=2\\ x=-\frac{3}{4} \end{array}\right.\)
a) x²-6x+5=0
b) 2x² -x-6=0
c) -4x²+3x+7=0
d) 4x²-5x-6=0
a) (x + 2)(3 – 4x) = x2 + 4x + 4
b) x(2x - 7) - 4x + 14 = 0
c) 3x - 15 = 2x(x - 5)
d) (2x + 1)(3x - 2) = (5x - 8)(2x + 1)
a. x (x²-1)=0
b. (x-1/2) 2x+5=0
c. x-2 (2/3x - 6)=0
d. x² - 2x=0
e.(x²-2x+1)-4=0
f.x(2x-1)=0
g.4x²+4x+1=0
h.x²-5x+6=0
i. 2x²+3x=0
Bài 8: Giải các phương trình tích sau:
4. a) 3x2 + 2x – 1 = 0 b) x2 – 5x + 6 = 0
c) x2 – 3x + 2 = 0 d) 2x2 – 6x + 1 = 0
e) 4x2 – 12x + 5 = 0 f) 2x2 + 5x + 3 = 0
g) x2 + x – 2 = 0 h) x2 – 4x + 3 = 0
i) 2x2 + 5x – 3 = 0 j) x2 + 6x – 16 = 0
5. a) 3x2 + 12x – 66 = 0 b) 9x2 – 30x + 225 = 0
c) x2 + 3x – 10 = 0 d) 3x2 – 7x + 1 = 0
e) 3x2 – 7x + 8 = 0 f) 4x2 – 12x + 9 = 0
g) 3x2 + 7x + 2 = 0 h) x2 – 4x + 1 = 0
i) 2x2 – 6x + 1 = 0 j) 3x2 + 4x – 4 = 0
giải phương trình tícha, 3x-1=0 b, 5x-2=x+4c, 2.(4-2x)-1 =x-3d, 2x-1/3 - x+2/6=3x e, (2x-1).(x.x-6)=0f, (x+2) .(5-4x)=x.x+4x+4
Bài 1 : Giải các phương trình sau:1) 5-(x-6)=4(3-2x) 2) (x-3)(x+4)-2(3x-2)=(x-4)2 3)3-x(1-3x)=5(1-2x) 4)9x-1=(3x+1)(4x+1) 5)2x(x-1)=x2-1 6)x2-5x2+6x=0 7)x2+4x-5=0 8)x3+9x2-4x-36=0
a) (5x-15)(4+6x)=0
b) (2x-1)(5x-6)(1/2x-3/4)=0
c) (3-4x)(2x-3/4-x-4/3)=0
d) (2/3x-1/6)[5(x-1)-3/2-(2-3)(x-1)/3]=0
5/ (x2 – 4) + (x – 2)(4 – 2x) = 0
6/ x(2x – 7) – 4x + 14 = 0 7/ x2 – x – (3x – 3) = 0
8/ (x2 – 2x + 1) – 4 = 0 9/ 4x2 + 4x + 1 = x2
10/ x2 – x = - 2x + 2 11/ x2 – 5x + 6 = 0
11/ x^2 -- 5x + 6 = 0
Câu 11 là x mũ 2 nha giúp dùm e nha anh chị .
1,Giải PT sau
a, (5x+3)(x2+4)(x-4)=0
b, (4x-1)(x-3)-(x-2)(5x+2)=0
c, (x+3)(x-5)+(x+3)(3x-4)=0
d, (x+6)(3x-1)+x2-36=0
e, 0,75x(x+5)=(x+5)(3-1,25x)