Question

a) 2x³ ( 2x - 3 ) - x² ( 4x² - 6x + 2 ) = 0

b) 2x ( x - 5 ) - x ( 3 + 2x ) = 0

c) x ( x - 4 ) - ( x² - 8 ) = 0

 

Answer 1

a: \(\Leftrightarrow4x^4-6x^3-4x^4+6x^3-2x^2=0\)

=>-2x²=0

=>x=0

b: \(\Leftrightarrow2x^2-10x-3x-2x^2=0\)

=>-13x=0

hay x=0

c: \(\Leftrightarrow x^2-4x-x^2+8=0\)

=>-4x=-8

hay x=2