Question

 Tìm x biết:

a, 16x² – 9(x + 1)²= 0

b,  x2 (x – 1) – 4x2 + 8x – 4 = 0

c,  x(2x – 3) – 2(3 – 2x) = 0

d, (x – 3)(x² + 3x + 9) – x(x + 2)(x – 2) = 1

e, 4x² + 4x – 6 = 2

f, 2x² + 7x + 3 = 0

Answer 1

e: ta có: \(4x^2+4x-6=2\)

\(\Leftrightarrow4x^2+4x-8=0\)

\(\Leftrightarrow\left(x+2\right)\left(x-1\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x=-2\\x=1\end{matrix}\right.\)

f: Ta có: \(2x^2+7x+3=0\)

\(\Leftrightarrow\left(x+3\right)\left(2x+1\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x=-3\\x=-\dfrac{1}{2}\end{matrix}\right.\)