Question

5\(\sqrt{25a^2}\) -25a

Answer 1

Ta có : \(5\cdot\sqrt{25\cdot a^2}=5\cdot5\cdot a=25a\)

Vậy 5*\(\sqrt{25\cdot a^2}\)-25a=0

Answer 2

5\(\sqrt{25a^2}-25a\)

=5 /5a/ - 25a

=5 . 5a - 25a

=25a - 25a=0

Answer 3

\(5\sqrt{25a^2}-25a=5.\left|5a\right|-25a=5.5a-25a=25a-25a=0\)