=>x(3y+2)+y+2/3=5/3
=>(y+2/3)(3x+1)=5/3
=>(3x+1)(3y+2)=5
=>\(\left(3x+1;3y+2\right)\in\left\{\left(1;5\right);\left(5;1\right);\left(-1;-5\right);\left(-5;-1\right)\right\}\)
=>\(\left(x,y\right)\in\left\{\left(0;1\right);\left(\dfrac{4}{3};-\dfrac{1}{3}\right);\left(-\dfrac{2}{3};-\dfrac{7}{3}\right);\left(-2;-1\right)\right\}\)
Đúng 0
Bình luận (0)
