2x-\(\dfrac{1}{x}\left(x+1\right)\)=\(\dfrac{1}{x}\)(đk x\(\ne\)0)
<=>2x\(^2\)-x-1=1
<=>2x\(^2\)-x-2=0
x1=<=>
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2x-\(\dfrac{1}{x}\left(x+1\right)=\dfrac{1}{x}\)(đk x\(\ne\)0)
<=>2x\(^2\)-x-1=1
<=>2x\(^2\)-x-2=0
<=>
<=>(thỏa mãn x\(\ne\)0)
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