\(\dfrac{x+23}{x+40}=\dfrac{3}{4}\)(ĐKXĐ: \(x\ne-40\))
=>\(4\left(x+23\right)=3\left(x+40\right)\)
=>4x+92=3x+120
=>4x-3x=120-92
=>x=28(nhận)
\(\dfrac{23+x}{40+x}=\dfrac{3}{4}\\ =>4\left(23+x\right)=3\left(40+x\right)\\ =>92+4x=120+3x\\ =>4x-3x=120-92\\ =>x=28\)