=>8-x3=19
=>x3=-11
hay \(x=\sqrt[3]{-11}\)
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Bài 19 Rút gọn
1) (x+2)^2+(3-x)^2
2) (4-x)^2 -(x-3)^2
3) (x-5)(x+5)-(x+5)^2
4) (x-3)^2-(x-4)(x+4)
5) (y^2 -6y+9)-(3-y)^2
6. (2x+3)² –(2x–3).(2x+3)
1) 2x – (3 – 5x) = 4( x +3)
2) 5(2x-3) - 4(5x-7) =19 - 2(x+11)
3) 5x - 4(6-x)(x + 3) = (4-2x)(3-2x) + 2
4) (x - 1)3 - (3x + 2)(-12) = (x2 + 1)(x - 2) - x2
5) (3x -1)2 - (x +3)(2x-1) = 7(x + 1)(x -2) -3x
mn giúp mình vs
Bài 19 rút gọn
1) (x+2)^2+(3-x)^2
2) (4-x)^2-(x-3)^2
3) (x-5)(x+5)-(x+5)^2
4)(x-3)^2-(x-4)(x+4)
5) (y^2-6y+9)-(3-y)^2
6) (2x+3)^2-(2x-3)(2x+3)
Tìm x biết
x^3 + 6x^2 +12x= 19
5(x + 9)^2(x - 4)^3 - 10(x + 9)^3(x - 4)^2 = 0
(2x + 3)^2 + (x - 2)^2 - 2(2x +3 )(x - 2)
a, Tính x^20 - 19x^19 + 18x^18 - 17x^17 + 16x^16 - 15x^15 với x= 19
b, tính: x^4 + y^4 - 2x^2y^2 biết x^2 + y^2 = 1
Tim x x(x+5)(x-5) - (x+2)(x^2-2x+4)=5
(x+1)^3 - (x-1)^3 -6(x-1)^2 = -19
Tìm x.
a) 9x^2 – 6x – 3 = 0
b) x^3 + 9x^2 + 27x + 19 = 0
c) x(x + 5)(x – 5) – (x + 2)(x^2 – 2x + 4) = 3
tìm x
a,(3x-4)(3x+4)-(3x+1)2=0
b,(2x-5)2-(2x+1)(2x-1)=0
c,(3x-1)2-2(3x-1)(-3x)+(x-3)2=25
d,(x-1)(x2+x+1)=7
e,(x+2)(x2-2x+4)=-19
giút gọn
a,(x-1)(x2+x+1)-(x+2)(x2-2x+4)
b,(x-2)(x2+2x+4)-(x+2)(x-2)-x(x2-2)
c,(2x-1)(4x2+2x+1)+(2x+1)(4x2-2x+1)
Bài 3 : Tìm x biết
a) (x-2)^2-x(x-3)=0
b) (x+3)(2x+1)-2(x-1)^2=0
c) (4x-5)^2=9(2-5x)^2
d) X^2-6x-13=0
e) (x+2)(x^2-2x+4)-x(x^2+2)=15
f) X^3-6x^2+12x-19=0
1. Rút Gọn
a) -5x (x-3).(2x+4)-(x+3)(x-3)+(5x-2)(3x+4)
b) (4x-1)x(3x+1)-5x^2x(x-3)-(x-4)x(x-5)-7(x^3-2x^2+x-1)
c) (5x-7)(x-9)-(3-x)(2-5x)-2x(x-4)
d)(5x-4)(x+5)-(x+1)(x^2-6)-5x+19
e)(9x^2-5)(x-3)-3x^2(3x+9)-(x-5)(x+4)-9x^3
g) (x-1)^2 - (x+2)^2
Thanks mn nhiều ạ