Question

1.\(\sqrt{-4x^2+25}=x\)

2.\(\sqrt{3x^2-4x+3}=1-2x\)

3. \(\sqrt{4\left(1-x\right)^2}-\sqrt{3}=0\)

4.\(\dfrac{3\sqrt{x+5}}{\sqrt{ }x-1}< 0\)

5. \(\dfrac{3\sqrt{x-5}}{\sqrt{x+1}}\ge0\)

Answer 1

Answer 2

Answer 3

Answer 4

Answer 5

1: Ta có: \(\sqrt{-4x^2+25}=x\)

\(\Leftrightarrow-4x^2+25=x^2\)

\(\Leftrightarrow-5x^2=-25\)

\(\Leftrightarrow x^2=5\)

hay \(x=\sqrt{5}\)

2: Ta có: \(\sqrt{3x^2-4x+3}=1-2x\)

\(\Leftrightarrow3x^2-4x+3=4x^2-4x+1\)

\(\Leftrightarrow4x^2+1-3x^2-3=0\)

\(\Leftrightarrow x^2=2\)

hay \(x=-\sqrt{2}\)