\(\dfrac{1}{6}+\dfrac{x}{4}=2-\dfrac{x}{3}\\ =>\dfrac{x}{4}+\dfrac{x}{3}=2-\dfrac{1}{6}\\ =>\dfrac{7x}{12}=\dfrac{11}{6}\\ =>7x=\dfrac{12\cdot11}{6}=22\\ =>x=\dfrac{22}{7}\)
`1/6 +x/4 = 2- x/3`
`=> x/4 + x/3 = -1/6 +2`
`=> 3x/12 + 4x/12 = 11/6`
`=> 7x/12 = 11/6`
`=> 7x = 22`
`=> x = 22/7`
Vậy `x= 22/7`