1.4:
a: =>3x-16=2*7=14
=>3x=30
=>x=10
1.3:
\(=\dfrac{21\left(4\cdot34-64\right)}{42\cdot9}=\dfrac{1}{2}\cdot\dfrac{4\left(34-16\right)}{9}=\dfrac{1}{2}\cdot4\cdot2=4\)
`@` `\text {Answer}`
`\downarrow`
`i)`
`(84*34-21*64) \div (42*9)`
`= (21*4 * 34 - 21 * 4* 16) \div (42 * 9)`
`= 84*(34 - 16) \div (42*9)`
`= 84*18 \div 42*9`
`= 1512 \div 378`
`= 4`
`1.4`
`a)`
`(3x - 2^4) * 7^3 = 2*7^4`
`=> (3x - 2^4) = 2*7^4 \div 7^3`
`=> (3x-2^4) = 2*7`
`=> 3x - 2^4 = 14`
`=> 3x = 14 + 2^4`
`=> 3x = 30`
`=> x = 30 \div 3`
`=> x = 10`
Vậy, `x = 10.`