\(49,=\dfrac{38}{5}-\left(\dfrac{19}{7}+\dfrac{28}{5}\right)\)
\(=\dfrac{38}{5}-\dfrac{19}{7}-\dfrac{28}{5}\)
\(=\left(\dfrac{38}{5}-\dfrac{28}{5}\right)-\dfrac{19}{7}\)
\(=2-\dfrac{19}{7}=-\dfrac{5}{7}\)
\(50,=\dfrac{25}{81}.\dfrac{15}{22}=\dfrac{125}{594}\)
Câu 50 tus sửa đề
\(-\dfrac{1}{9}.\dfrac{15}{22}:\dfrac{-25}{9}=-\dfrac{1}{9}.\dfrac{15}{22}.\dfrac{-9}{25}=\dfrac{15}{22}.\dfrac{1}{25}=\dfrac{3}{110}\)
Bài 1 :
Câu 49 . = 38/5 - ( 19/7 + 28/5 )
= 38/5 - 19/7 - 28/5
= ( 38/5 - 28/5 ) - 19/7
= 2 - 19/7 = -5/7
Câu 50 . = ( -1/9 : -25/9 ) . 15/22
= 1/25 . 15/22 = 3/110
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