\(cota=-7=>tana=\dfrac{1}{cota}=\dfrac{-1}{7}\\ 1+tan^2a=\dfrac{1}{cos^2a}\\ =>cosa=\sqrt{\dfrac{1}{1+tan^2a}}=\sqrt{\dfrac{1}{1+\left(-\dfrac{1}{7}\right)^2}}=\dfrac{7}{5\sqrt{2}}=\dfrac{7\sqrt{2}}{10}\\ =>sina=\sqrt{1-cos^2a}=\sqrt{1-\left(\dfrac{7\sqrt{2}}{10}\right)^2}=\dfrac{\sqrt{2}}{10}\)
tana=-1/7
\(\dfrac{1}{sin^2a}=1+cot^2a\Rightarrow\dfrac{1}{sin^2a}=1+49=50\Rightarrow sina=\pm\dfrac{1}{\sqrt{50}}\) ( loại )
Vậy ko có giá trị sin;cos tm