a: \(\dfrac{2}{9}\cdot\dfrac{3}{4}-\dfrac{11}{9}\cdot0,75\)
\(=\dfrac{2}{9}\cdot\dfrac{3}{4}-\dfrac{11}{9}\cdot\dfrac{3}{4}\)
\(=\dfrac{3}{4}\left(\dfrac{2}{9}-\dfrac{11}{9}\right)=\dfrac{3}{4}\cdot\dfrac{-9}{9}=-\dfrac{3}{4}\)
b: \(\left(1-\dfrac{1}{3}\right)^{12}:\left(\dfrac{2}{3}\right)^{10}-1\dfrac{4}{9}-2022^0\)
\(=\left(\dfrac{2}{3}\right)^{12}:\left(\dfrac{2}{3}\right)^{10}-1-\dfrac{4}{9}-1\)
\(=\left(\dfrac{2}{3}\right)^2-\dfrac{4}{9}-2=-2\)
c: \(\left(\dfrac{3}{7}\right)^3\cdot\left(\dfrac{7}{6}\right)^3+\dfrac{2}{3}:\left(\dfrac{4}{3}\right)^2\)
\(=\left(\dfrac{3}{7}\cdot\dfrac{7}{6}\right)^3+\dfrac{2}{3}:\dfrac{16}{9}\)
\(=\left(\dfrac{3}{6}\right)^3+\dfrac{2}{3}\cdot\dfrac{9}{16}\)
\(=\dfrac{1}{8}+\dfrac{3}{8}=\dfrac{4}{8}=\dfrac{1}{2}\)
d: \(\left(\dfrac{2}{5}\right)^2+5\dfrac{1}{2}\cdot\left(4,5-2,5\right)+\dfrac{2^3}{-4}\)
\(=\dfrac{4}{25}+\dfrac{11}{2}\cdot2+\dfrac{8}{-4}\)
\(=\dfrac{4}{25}+11-2=\dfrac{4}{25}+9=\dfrac{4+9\cdot25}{25}=\dfrac{225+4}{25}=\dfrac{229}{25}\)