a, \(3,35\approx3,4\)
\(129,33\approx129,3\)
\(-2,999\approx-2,1\)
\(-15,06\approx-15,1\)
\(0,55555\approx0,6\)
b, Ta có: \(2^{3000}=\left(2^3\right)^{1000}=8^{1000}\)
\(3^{2000}=\left(3^2\right)^{1000}=9^{1000}\)
Vì \(8< 9\) nên \(8^{1000}< 9^{1000}\)
Hay \(2^{3000}< 3^{2000}\)