câu a)
\(\dfrac{11}{18}< \dfrac{17}{24}\)
câu b)
\(\dfrac{29}{24}>\dfrac{17}{16}\)
câu c)
\(\dfrac{-5}{12}>\dfrac{-11}{16}\)
câu d)
\(\dfrac{-13}{8}< \dfrac{-17}{12}\)
a: \(\dfrac{11}{18}=\dfrac{11\cdot4}{18\cdot4}=\dfrac{44}{72}\)
\(\dfrac{17}{24}=\dfrac{17\cdot3}{24\cdot3}=\dfrac{51}{72}\)
mà 44<51
nên \(\dfrac{11}{18}< \dfrac{17}{24}\)
b: \(\dfrac{29}{24}=\dfrac{29\cdot2}{24\cdot2}=\dfrac{58}{48}\)
\(\dfrac{17}{16}=\dfrac{17\cdot3}{16\cdot3}=\dfrac{51}{48}\)
mà \(\dfrac{58}{48}>\dfrac{51}{48}\left(58>51\right)\)
nên \(\dfrac{29}{24}>\dfrac{17}{16}\)
c: \(\dfrac{-5}{12}=\dfrac{-5\cdot4}{12\cdot4}=\dfrac{-20}{48}\)
\(\dfrac{-11}{16}=\dfrac{-11\cdot3}{16\cdot3}=\dfrac{-33}{48}\)
mà \(-\dfrac{20}{48}>-\dfrac{33}{48}\left(-20>-33\right)\)
nên \(\dfrac{-5}{12}>\dfrac{-11}{16}\)
d: \(\dfrac{-13}{8}=\dfrac{-13\cdot3}{8\cdot3}=-\dfrac{39}{24}\)
\(\dfrac{-17}{12}=\dfrac{-17\cdot2}{12\cdot2}=\dfrac{-34}{24}\)
mà -39<-34
nên \(-\dfrac{13}{8}< -\dfrac{17}{12}\)